AP计算机教程9-15:困难多选题
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Assume that the following declaration appears in a client program Base b = new Derived();. What is the result of the call b.methodOne()?
public class Base
{
public void methodOne()
{
System.out.print("A");
methodTwo();
}
public void methodTwo()
{
System.out.print("B");
}
public static void main(String[] args)
{
Base b = new Derived();
b.methodOne();
}
}
class Derived extends Base
{
public void methodOne()
{
super.methodOne();
System.out.print("C");
}
public void methodTwo()
{
super.methodTwo();
System.out.print("D");
}
}
super.methodOne()中调用的methodTwo()会是Derived中定义的。1
Given the class definitions of Point2D and Point3D below, which of the constructors that follow (labeled I, II, and III) would be valid in class Point3D?
class Point2D {
public int x;
public int y;
public Point2D() {}
public Point2D(int x,int y) {
this.x = x;
this.y = y;
}
// other methods
}
public class Point3D extends Point2D
{
public int z;
// other code
}
// possible constructors for Point3D
I. public Point3D() {}
II. public Point3D(int x, int y, int z)
{
super(x,y);
this.z = z;
}
III. public Point3D(int x, int y)
{
this.x = x;
this.y = y;
this.z = 0;
}
注意
x和y均是public,都能在child class中被直接访问。4
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