AP计算机教程9-15:困难多选题
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Assume that the following declaration appears in a client program Base b = new Derived();
. What is the result of the call b.methodOne()
?
public class Base { public void methodOne() { System.out.print("A"); methodTwo(); } public void methodTwo() { System.out.print("B"); } public static void main(String[] args) { Base b = new Derived(); b.methodOne(); } } class Derived extends Base { public void methodOne() { super.methodOne(); System.out.print("C"); } public void methodTwo() { super.methodTwo(); System.out.print("D"); } }
super.methodOne()
中调用的methodTwo()
会是Derived
中定义的。1
Given the class definitions of Point2D
and Point3D
below, which of the constructors that follow (labeled I, II, and III) would be valid in class Point3D
?
class Point2D { public int x; public int y; public Point2D() {} public Point2D(int x,int y) { this.x = x; this.y = y; } // other methods } public class Point3D extends Point2D { public int z; // other code } // possible constructors for Point3D I. public Point3D() {} II. public Point3D(int x, int y, int z) { super(x,y); this.z = z; } III. public Point3D(int x, int y) { this.x = x; this.y = y; this.z = 0; }
注意
x
和y
均是public
,都能在child class中被直接访问。4
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